318A - Even Odds - CodeForces Solution

math *900

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Python Code: 

import math
s = input()
a, b = s.split(" ")
a = int(a)
b = int(b)
r = 0
if b <= math.ceil(a / 2):
    print(1 + 2 * (b - 1))
else:
    print(2 * (b - math.ceil(a / 2)))

C++ Code: 

#include<iostream>
#include<string>
#include<algorithm>
#include<math.h>
#include<vector>
#include<string>
#include<set>
using namespace std;
typedef long long ll;
typedef bool bl;
typedef double d;
#define fo(a, b, n) for(int a = 0 ;a < n;a++)

int main()
{
	ll n, k, c;
	cin >> n >> k;
	vector<int > v;
	if (n % 2 == 0)
		c = n / 2;
	else
		c = (n / 2) + 1;
	if (k <= c)
		cout << (2 * k - 1);
	else
	{
		if (n % 2 != 0)
		{
			ll z = n - k;
			cout << k - z - 1;
		}
		else
		{
			ll z = n - k;
			cout << k - z;
		}
	}
	
	
	system("pause");
	return 0;
}


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